

for
Section 3: Mean, Median, Variance and Standard Deviation
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1. E(X) = 3/2, Var(X) = 3/4,
(X) = 31/2/2
3. E(X) = 20/3, Var(X) = 50/9,
(X) = 501/2/3
5. E(X) = 3/8, Var(X) = 0.05975,
(X) = 0.2437
7. E(X) = 0.3863, Var(X) = 0.03909,
(X) = 0.1977
9. E(X) = 10, Var(X) = 100,
(X) = 10
11. E(X) =
33.3333, Var(X) = 1111.1111,
(X) = 33.3333
13. E(X) = 3/2, Var(X) = 3/4,
(X) = /2
15. E(X) = 1, Var(X) = 1,
(X) = 1
17. E(X) = 0.4286, Var(X) = 0.05442,
(X) = 0.2333
19. E(X) = 0.6774, Var(X) = 0.0304,
(X) = 0.1742
21. E(X) = 0.4413, Var(X) = 0.07852,
(X) = 0.2802
23. E(X) = 0.8862, Var(X) = 0.2146,
(X) = 0.4633
25. 2
27. 0.2310
29.
23.1049
30. 34.6574
31. 0.2929
33. 0.25
35-40. Proofs
41. 0.35
43. 0.61
45. 0.65
47. 0.41
49. 0.83
51. E(X2) = 3, E(X2)
E(X)2 = 3/4
53. E(X2) = 50, E(X2)
E(X)2 = 50/9
55. E(X2) = 1/5, E(X2)
E(X)2 = 0.059375
57. E(X2) = 0.1883, E(X2)
E(X)2 = 0.0391
59. E(X2) = 200, E(X2)
E(X)2 = 100
61. Comparing answers suggests that E(X2)
E(X)2 = Var(X). Thus, E(X2) = E(X)2 + Var(X).
63. $25,000
65. 34 months
67. 8,267 years
69. 100,000,000 years
71. 5.3009
73. 100.4988
75 (a)
= 2.5556, f(x) = 16.1975x2.5556(1
x)
75 (b) M(X) = 0.66, a little smaller than the mean. This indicates that more students scored below the mean than above it.
77.
79. Missing words: variance, median.
81. Values of X are more likely to be close to the mode than anywhere else. Thus an interval about the mode determines the most popular values of X.

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![]() | Stefan Waner (matszw@hofstra.edu) | ![]() | Steven R. Costenoble (matsrc@hofstra.edu) |