In words, EF' consists of all outcomes that are both in E and F'; that is, all outcomes whose sum is 4 and whose sum is even. Of all the outcomes whose sum is even, the only ones whose sum is 4 are (1, 3), (2, 2), and (3, 1). Therefore,

EF' = {(1, 3), (2, 2), (3, 1)}

Using sets,

E = {(1, 3), (2, 2), (3, 1)}
(outcomes whose sum is 4)
F' = {(1, 1), (1, 3), (1, 5), (2, 2), (2, 4), (2, 6), (3, 1), (3, 3), (3, 5), (4, 2), (4, 4), (4, 6), (5, 1), (5, 3), (5, 5), (6, 2), (6, 4), (6, 6)}
(outcomes whose sum is even)

Therefore,

EF' = {(1, 3), (2, 2), (3, 1)}.