We have

	1 2u3	du	=	1 2 u3 du	(integrand in exponent form)
			=	1 2 u3 du	(slip the constant outside)
			=	1 2 u2 2 + C	(evaluate the integral)
			=	1 4u2 + C	(simplify)
			=	1 4(2x22x+5)2 + C	(substitute back)

You can enter this as

-1/(4(2x^2-2x+5)^2) + C     or     -(1/4) (2x^2-2x+5)^(-2) + C

Press here for the entire calculation.

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