u = 2x22x+5 du dx = 4x2 = 2(2x1) dx = 1 2(2x1) du

Thus,

2x1 (2x22x+5)3 dx	=	2x1 u3 1 2(2x1) du	(substituting for u and dx)
	=	1 2u3 du	(canceling the term (2x1))
	=	1 2 u3 du	(integrand in exponent form)
	=	1 2 u3 du	(slip the constant outside)
	=	1 2 u2 2 + C	(evaluate the integral)
	=	1 4u2 + C	(simplify)
	=	1 4(2x22x+5)2 + C	(substitute back)

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