Since the given function is a quotient, we must use the quotient rule:

d dx	ex ex ex + ex

	=	(ex+ex) (d/dx)(exex) (exex)(d/dx)(ex+ex) (ex+ex)2
	=	(ex+ex)(ex+ex) (exex)(exex) (ex+ex)2	(since the derivative of ex is ex)
	=	(e2x+2exex+e2x) (e2x2exex+e2x) (ex+ex)2	(expanding the terms)
	=	2exex + 2exex (ex+ex)2	(because the other terms cancel)
	=	4 (ex+ex)2	(because exex = 1)

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