Using the Chain Rule Formula
From the table above, we find:
![]() dx |
ln (u) | = | ![]() u |
![]() dx |
Therefore,
![]() dx |
ln( x2+2x 1)
| = | ![]() x2+2x 1 |
![]() dx |
(x2+2x 1) |
| = | ![]() x2+2x 1 |
(2x+2) | |||
| = | ![]() x2+2x 1 |
||||
Using the Verbal Form of the Chain Rule
The verbal form of the chain rule above states:
1) is the reciprocal of (x2+2x
1), times the derivative of (x2+2x
1).
That is,
1) is the reciprocal of (x2+2x
1), times (2x+2).
If you now write this in symbols, you get the same answer as above.
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