The Calculator Thought Experiment (CTE) tells us that the expression

(x² 1)³(3x + 4)¹

d dx	[(x2 1)3(3x + 4)1]

=

d dx

(x2 1)3

(3x + 4)1

+

(x2 1)3

d dx

(3x + 4)1

=	(3)(2x)(x2 1)2(3x + 4)1 + (x2 1)3(1)(3)(3x + 4)2
=	6x(x2 1)2(3x+4)1 3(x2 1)3(3x+4)2

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