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The Chain Rule
If the function f has derivative f' and the function u has derivative du/dx, then the composite function f(u) is differentiable, and
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Proof From the definition of the derivative,
h |
Thus,
h |
- | u'(x) |
If we take v to be the quantity
| v | = | h |
- | u'(x) | , |
then v0 as h
0. If we solve this equation for u(x+h), we get
where v0 as h
0
Now the same is true for f.
where w0 as h
0.
What we are after is the derivative of f(u(x)). Thus we need to calculate the limit of
h |
First look at the numerator: f(u(x+h)) - f(u(x)). If we use formula (I) to substitute for u(x+h) we get
Now we use formula (II) to rewrite f [u(x) + (u'(x) + v)h]:
Subtracting f(u(x)) from both sides gives
Putting (III) and (IV) together now gives
This is the numerator of the expression we are after. Dividing by h gives
h |
= | h |
= | (f'(u(x)) + w)(u'(x) + v). |
Now let h0. Since both v and w
0, we obtain
| lim h |
h |
= | f'(u(x)) u'(x), |
which is the chain rule.

